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Swimming Pool Problem

Hazel Taintor and GiGi Chavez

Problem Statement

In this problem, we will use Pythagorean Theorem to find out how long it would take to swim from corner to corner on three different sized pools. Pythagorean Theorem is a squared plus b squared equals c squared. Taking the numbers that are already given, they would be squared and then added. The sum would then be square rooted and that is the number that is missing.

Olympic Sized Pool

Square root of 33,620=183.36 ft.

So it would be 183.36 ft. to get from one corner of the pool to the other diagonally.

6,724+26,896=33,620

82²+164²=c²

a²+b²=c²

164 ft.

82 ft.

Square root of 980=31.30 ft.

So it would be 31.30 ft. to get from one corner of the pool to the other diagonally.

Average Pool

196+784=980

14²+28²=c²

a²+b²=c²

28 ft.

14 ft.

Average Inflatable Pool

Square root of 136=11.66 ft.

So it would be 11.66 ft. to get from one corner of the pool to the other diagonally.

36+100=136

6²+10²=c²

a²+b²=c²

10 ft.

6 ft.