We will be making a booklet which will demonstrate our understand of Pythagorean theorem

Pythagorean Theorem

**It's soooo easy to understand!**

By: Rumi Sevilla-Hernandez & Annie Friginal

**What is our Book About ?**

**Our class has been studying Pythagorean Theorem!**

To demonstrate our understanding of this topic, we have provided three questions as well as the steps on how to solve it using Pythagorean Theorem!

**How to use Pythagorean Theorem (and Question 1)**

**On a professional baseball diamond there are 90 feet between ****the bases. How far is a throw from first to third base?**

In order to figure out the answer, we must use Pythagorean theorem. Pythagorean theorem is a mathematical formula: a squared plus b squared equals c squared (like the picture shown above). It can be used to calculate a given side length of a triangle.

**Let's Break down the Question!**

**We understand that there are 90 ft between each base in the baseball diamond. **

Therefore to be able to throw a ball from 1st base to 3rd base, we cut the diamond diagonally. This makes a triangle. We now have the ability to apply Pythagorean theorem to the triangle. One side which we know is 90 ft, represents "a squared". The other side also is 90 ft and represents "b squared". The diagonal side which we do not know the length of yet, represents "c squared".

**Let's solve it!**

**To solve for c squared **

we first have to add A squared (90^2 ft) with B squared (90^2 ft). This equals 16,200 ft which is equal to c^2. However, we still have to get c by itself. In order to do this, we must calculate the square root of c^2 (16,200 ft). After using a calculator, we found that c, also known as the length a baseball can be thrown from 1st base to 3rd base, is 127.3 ft (rounded).

**Question 2)**

**On a professional tee ball diamond there are 30 feet between ****the bases. How far is a throw from first to third base?**

In order to figure out the answer, we must use Pythagorean theorem again!

**Let's Break Down the Question!**

**We understand that there are 30 ft between each base in the teeball diamond. **

Therefore to be able to throw a ball from 1st base to 3rd base, we cut the diamond diagonally. This makes a triangle. We now have the ability to apply Pythagorean theorem to the triangle. One side which we know is 30 ft, represents "a squared". The other side also is 30 ft and represents "b squared". The diagonal side which we do not know the length of yet, represents "c squared".

**Let's solve it!**

**To solve for c squared **

we first have to add A squared (30^2 ft) with B squared (30^2 ft). This equals 1,800 ft which is equal to c^2. However, we still have to get c by itself. In order to do this, we must calculate the square root of c^2 (c^2 is 1,800). After using a calculator, we found that c, also known as the length a baseball can be thrown from 1st base to 3rd base is 42.4 ft (rounded).

**Question 3)**

**On a professional softball diamond there are 60 feet between ****the bases. How far is a throw from first to third base?**

In order to figure out the answer, we must use Pythagorean theorem again!

**Let's Break down the Question!**

**We understand that there are 30 ft between each base in the teeball diamond. **

Therefore to be able to throw a ball from 1st base to 3rd base, we cut the diamond diagonally. This makes a triangle. We now have the ability to apply Pythagorean theorem to the triangle. One side which we know is 60 ft, represents "a squared". The other side also is 60 ft and represents "b squared". The diagonal side which we do not know the length of yet, represents "c squared".

**Let's Solve It!**

**To solve for c squared **

we first have to add A squared (60^2 ft) with B squared (60^2 ft). This equals 7,200 ft which is equal to c^2. However, we still have to get c by itself. In order to do this, we must calculate the square root of c^2 (c^2 is 7,200). After using a calculator, we found that c, also known as the length a baseball can be thrown from 1st base to 3rd base is 84.85 ft (rounded).